Ta có:
\(\frac{9-x}{7}+\frac{11-x}{9}=2\)
\(\Rightarrow\frac{81-9x}{63}+\frac{77-7x}{63}=2\)
\(\Rightarrow\frac{81-9x+77-7x}{63}=2\)
\(\Rightarrow\frac{158-16x}{63}=2\)
\(\Rightarrow158-16x=2.63=126\)
\(\Rightarrow16x=158-126=32\)
\(\Rightarrow x=32:16=2\)
\(\Rightarrow\frac{x}{2}=\frac{y}{3}=\frac{z}{4}=\frac{2}{2}=1\)
\(\Rightarrow y=3;z=4\)
Vậy \(\Rightarrow x=2\); \(y=3;z=4\)