- Theo đề bài ta có:
\(\left(x-\dfrac{1}{2}\right)^2=0\)
\(\Rightarrow\left(x+\dfrac{1}{2}\right)^2=0^2\)
\(\Rightarrow x+\dfrac{1}{2}=0\)
\(\Rightarrow x=-\dfrac{1}{2}\)
- Vậy \(x=-\dfrac{1}{2}\)
\(\left(X-\dfrac{1}{2}\right)^2=0\\\)
\(\Leftrightarrow X-\dfrac{1}{2}=0\)
\(\Leftrightarrow X=-\dfrac{1}{2}\)
Vậy \(X=-\dfrac{1}{2}\)