Giải:
Để \(\dfrac{-4}{2x-1}\in Z\) thì:
\(-4⋮2x-1\)
\(\Leftrightarrow2x-1\inƯ\left(-4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
\(\Leftrightarrow2x\in\left\{0;2;-1;3;-3;5\right\}\)
\(\Leftrightarrow x\in\left\{0;1;-\dfrac{1}{2};\dfrac{3}{2};-\dfrac{3}{2};\dfrac{5}{2}\right\}\)
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