Question

tìm x biết (x-2)²-(x-3)(x+3)=6

(x-4)²-(x-2)(x+2)=6

Answer 1

(x-2)²-(x-3)(x+3)=6

\(\Rightarrow x^2-8x+16-\left(x^2-4\right)=6\)

\(\Rightarrow x^2-8x+16-x^2+4=6\)

\(\Rightarrow-8x+20=6\)

\(\Rightarrow-8x=-14\)

\(\Rightarrow x=\dfrac{7}{4}\)

Vậy \(x=\dfrac{7}{4}\)

Answer 2

Answer 3

(x-2)² -(x-3)(x+3)=6

x²-8x+16-(x²-4)=6

x²-8x+16-x²+4=6

-8x+20=6

-8x=-14

x=\(\frac{7}{4}\)

Vậy x =\(\frac{7}{4}\)