\(\frac{1}{2}-\left\{\frac{1}{3}-\left[\frac{1}{4}-\left(\frac{1}{5}-x\right)\right]\right\}=1\\ \Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+x=1\\ \Rightarrow x=1-\frac{13}{60}\\ \Rightarrow x=\frac{47}{60}\)
vậy ...
\(\frac{1}{2}-\left\{\frac{1}{3}-\left[\frac{1}{4}-\left(\frac{1}{5}-x\right)\right]\right\}=1\)
\(\Rightarrow\frac{1}{2}-\left\{\frac{1}{3}-\left(\frac{1}{4}-\frac{1}{5}+x\right)\right\}=1\)
\(\Rightarrow\frac{1}{2}-\left[\frac{1}{3}-\left(\frac{1}{20}+x\right)\right]=1\)
\(\Rightarrow\frac{1}{2}-\left(\frac{1}{3}-\frac{1}{20}-x\right)=1\)
\(\Rightarrow\frac{1}{2}-\left(\frac{17}{60}-x\right)=1\)
\(\Rightarrow\left(\frac{17}{60}-x\right)=\frac{1}{2}-1\)
\(\Rightarrow\frac{17}{60}-x=-\frac{1}{2}\)
\(\Rightarrow x=\frac{17}{60}+\frac{1}{2}\)
\(\Rightarrow x=\frac{47}{60}.\)
Vậy \(x=\frac{47}{60}.\)
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