a,
\(\left|x-1\right|=2x-5\\ \Rightarrow\left\{{}\begin{matrix}x-1=2x-5\\x-1=5-2x\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=4\\x=2\end{matrix}\right.\\ Vậyx\in\left\{4;2\right\}\)
b,
\(\left|\left|x+5\right|-4\right|=3\\ \Rightarrow\left[{}\begin{matrix}\left|x+5\right|-4=-3\\\left|x+5\right|-4=3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}\left|x+5\right|=1\\\left|x+5\right|=7\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x+5=1\\x+5=-1\end{matrix}\right.\\\left\{{}\begin{matrix}x+5=7\\x+5=-7\end{matrix}\right.\end{matrix}\right.\\ \left[{}\begin{matrix}\left\{{}\begin{matrix}x=-4\\x=-6\end{matrix}\right.\\\left\{{}\begin{matrix}x=2\\x=-12\end{matrix}\right.\end{matrix}\right.\\ vậyx\in\left\{-12;-6;-4;2\right\}\)
\(c.|10x+7|< 37\Leftrightarrow-37< 10x+7< 37\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>-\dfrac{44}{10}\\x< 3\end{matrix}\right.\) \(\Leftrightarrow-\dfrac{44}{10}< x< 3\)
Vậy ,........
\(d.\) Bạn có thể chia trường hợp hoặc lập bảng xét dấu nhé ( nếu chưa hiểu tối mình làm lại cho )