\(3x-\left|2x-1\right|=2\)
\(\Leftrightarrow\left|2x-1\right|=3x-2\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=3x-2\\2x-1=-\left(3x-2\right)\end{matrix}\right.\)
+) \(2x-1=3x-2\)
\(\Leftrightarrow3x-2x=-1+2\)
\(\Leftrightarrow x=1\left(tm\right)\)
+) \(2x-1=-\left(3x-2\right)\)
\(\Leftrightarrow2x-1=-3x+2\)
\(\Leftrightarrow2x+3x=3+1\)
\(\Leftrightarrow5x=4\)
\(\Leftrightarrow x=\dfrac{4}{5}\)
Vậy ...
Đúng 0
Bình luận (0)
