a) x(4x2-1)=0
=>x(2x-1)(2x+1)=0
=>\(\left[{}\begin{matrix}x=0\\2x-1=0\\2x+1=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=0\\2x=1\\2x=-1\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=\dfrac{-1}{2}\end{matrix}\right.\)
vậy x\(\in\) {-\(\dfrac{1}{2}\) ;0;\(\dfrac{1}{2}\) }