a/ 5x(4x - 3) + 6 - 8x = 0
<=> 5x(4x - 3) - 2(4x - 3) = 0
<=> (4x - 3)(5x - 2) = 0
<=> \(\left[{}\begin{matrix}4x-3=0\\5x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{2}{5}\end{matrix}\right.\)
b/ 5x(x-9) - x + 9 = 0
<=> 5x(x - 9) - (x - 9) = 0
<=> (x-9)(5x-1) = 0
<=> \(\left[{}\begin{matrix}x-9=0\\5x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=\dfrac{1}{5}\end{matrix}\right.\)
\(a.\)
\(5x\left(4x-3\right)+6-8x=0\)
\(\Rightarrow5x\left(4x-3\right)-2\left(4x-3\right)=0\)
\(\Rightarrow\left(5x-2\right)\left(4x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-2=0\\4x-3=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=\dfrac{3}{4}\end{matrix}\right.\)
Vậy : .............................
\(b.\)
\(5x\left(x-9\right)-x+9=0\)
\(\Rightarrow5x\left(x-9\right)-\left(x-9\right)=0\)
\(\Rightarrow\left(5x-1\right)\left(x-9\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5x-1=0\\x-9=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=9\end{matrix}\right.\)
Vậy : ........................
a) 5x(4x-3)+6-8x=0
<=> 5x(4x-3)-2(4x-3)=0
<=> (4x-3)(5x-2)=0
<=> \(\left[{}\begin{matrix}4x-3=0\\5x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{2}{5}\end{matrix}\right.\)
Vậy ....
b) 5x(x-9)-x+9 =0
<=> 5x(x-9)-(x-9)=0
<=> (x-9)(5x-1)=0
<=> \(\left[{}\begin{matrix}x-9=0\\5x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=\dfrac{1}{5}\end{matrix}\right.\)
vậy ....
