Lời giải:
\(|5x^2-1|=-|\frac{-4}{3}|=-\frac{4}{3}< 0\)
Ta biết giá trị của một trị tuyệt đối thì luôn không âm, mà \(-\frac{4}{3}< 0\) nên điều trên hoàn toàn vô lý
Do đó không tồn tại $x$ thỏa mãn.
Cần giúp nhanh vs
Bài 1. Tìm x
a) \(\left|x+\dfrac{7}{4}\right|=\dfrac{1}{2}\)
b) \(\left|2x+1\right|-\dfrac{2}{5}=\dfrac{1}{3}\)
c) \(3x.\left(x+\dfrac{2}{3}\right)=0\)
d) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\left(-\dfrac{1}{3}\right)\)
Bài 2. Tính nhanh
\(A=\dfrac{1}{100}-\dfrac{1}{100.99}-\dfrac{1}{99.98}-\dfrac{1}{98.97}-....-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
Tìm x biết :
a) \(\left|2x+3\right|\) + x = 4
b) \(\left|5x-3\right|=\left|x-7\right|\)
c) \(2.\left|x-1\right|-3x=7\)
d) \(\left|\dfrac{3}{5}-\dfrac{1}{2}x\right|>\dfrac{2}{5}\)
Tìm x biết
a) (5x-2)^10=(5x-2)^100
b)\(\left(\dfrac{2x-3}{4}\right)^{2016}\)+\(\left(\dfrac{3y+4}{5}\right)^{2018}\)=0
Tìm giá trị của các biểu thức sau :
\(P=\left(-0,5-\dfrac{3}{5}\right):\left(-3\right)+\dfrac{1}{3}-\left(-\dfrac{1}{6}\right):\left(-2\right)\)
\(Q=\left(\dfrac{2}{25}-1,008\right):\dfrac{4}{7}:\left[\left(3\dfrac{1}{4}-6\dfrac{5}{9}\right).2\dfrac{2}{17}\right]\)
Tìm x biết
a)\(\left(3x+\dfrac{1}{3}\right)\left(x-\dfrac{1}{2}\right)=0\)
b)\(\left(x-\dfrac{3}{2}\right)\left(2x+1\right)>0\)
c)\(\left(2-x\right)\left(\dfrac{4}{5}-x\right)< 0\)
d)\(\left(x-\dfrac{4}{7}\right):\left(x+\dfrac{1}{2}\right)>0\)
e)\(2\left(x+1\right)-\dfrac{1}{3}.\left(x-1\right)=\dfrac{2}{3}\)
k)\(\left|4x-0,2\right|=0,2\)
Bài 1
\(\left(-2\right)^3.\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
Bài 2
a) \(4\dfrac{1}{3}:\dfrac{x}{4}=6:0,3\)
b) \(\left(2^3:4\right).2^{\left(x+1\right)}=64\)
a) \(\left[\left(\dfrac{3}{5}\right)^2-\left(\dfrac{2}{5}\right)^2\right]\). X = \(\left(\dfrac{1}{5}\right)^3\)
b) \(1\dfrac{2}{5}.x+\dfrac{3}{7}=\dfrac{-4}{5}\)
c) \(\left(3x-2\right)^2=9\)
d) \(|x+\dfrac{1}{3}|-4=-1\)
1. \(\left|\dfrac{-3}{5}+\dfrac{1}{7}\right|+\dfrac{5}{7}:\left(\dfrac{-5}{2}\right)\)
2. \(\dfrac{64}{4^{\left(x+1\right)}}=4\) với (x ϵ N)
Tìm X
(\(\dfrac{2}{5}+\dfrac{1}{4}\))(\(\dfrac{-x}{3}+\dfrac{1}{2}\))+\(\dfrac{2}{3}=\dfrac{7}{4}\)
\(\left(\dfrac{3}{5}-\dfrac{X}{2}\right)\left(\dfrac{4}{5}+\dfrac{1}{2}\right)-\dfrac{4}{3}=\dfrac{3}{2}\)
