Question

Tìm x

2x\(^2\)=x

Answer 1

Ta có: \(2x^2=x\)

\(\Rightarrow2.x.x=x\)

\(\Rightarrow\left(2.x\right).x=x.1\)

\(\Rightarrow2.x=1\)

\(\Rightarrow x=\dfrac{1}{2}\)

Vậy \(x=\dfrac{1}{2}\) .

Answer 2

Ta có: 2x² = x

➩2.x.x=x

Answer 3

V

Vậy...

Answer 4

2x²=x

<=> 2x²-x=0

<=> x(2x-1)=0

<=> ĐKXĐ: x=0, 2x-1=0

<=> x=0, \(\dfrac{1}{2}\)

Answer 5

2x² = x

=> 2x² - x = 0

=> x(2x-1) = 0

=> \(\left[{}\begin{matrix}x=0\\2x-1=0\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\end{matrix}\right.\)

Vậy x \(\in\) {0 ; \(\dfrac{1}{2}\) }