Để A là số tự nhiên thì \(\left\{{}\begin{matrix}2\sqrt{n}-8+7⋮\sqrt{n}-4\\\left[{}\begin{matrix}n>16\\n< \dfrac{1}{4}\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\sqrt{n}-4\in\left\{1;-1;7;-7\right\}\\\left[{}\begin{matrix}n>16\\n< \dfrac{1}{4}\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow n\in\left\{25;121\right\}\)