- Với \(x=-2\Rightarrow A=0\)
- Với \(x\ne-2\)
\(\Leftrightarrow Ax^2+Ax+A=x+2\)
\(\Leftrightarrow Ax^2+\left(A-1\right)x+A-2=0\)
\(\Delta=\left(A-1\right)^2-4A\left(A-2\right)\ge0\)
\(\Leftrightarrow-3A^2+6A+1\ge0\)
\(\Rightarrow\frac{3-2\sqrt{3}}{3}\le A\le\frac{3+2\sqrt{3}}{3}\)