\(A=\dfrac{3x^2+9x+17}{3x^2+9x+7}=1+\dfrac{10}{3x^2+9x+7}=1+\dfrac{10}{3\left(x^2+2.x.\dfrac{9}{2}+\dfrac{81}{4}\right)-\dfrac{215}{4}}\\ =1+\dfrac{10}{3\left(x+\dfrac{9}{2}\right)^2-\dfrac{215}{4}}\le\dfrac{35}{43}\)
Câu khác giải TT
Tìm GTNN, GTLN. a, A=-3x^2+6x-2 b, B=4-16x^2-8x c, C=2-5x^2-y^2-4xy+2x d, D=1/x^2+2x+3 e, E=-x^2+5x-7
Tìm x:
a) \(3x\left(3x-8\right)-9x^2+8=0\)
b)\(6x-15-x\left(5-2x\right)=0\)
c) \(x^3-16x=0\)
d) \(2x^2+3x-5=0\)
e) \(3x^2-x\left(3x-6\right)=36\)
f) \(\left(x+2\right)^2-\left(x-5\right)\left(x+1\right)=17\)
g) \(\left(x-4\right)^2-x\left(x+6\right)=9\)
h) \(4x\left(x-1000\right)-x+1000=0\)
i) \(x^2-36=0\)
j) \(x^2y-2+x+x^2-2y+xy=0\)
k) \(x\left(x+1\right)-\left(x-1\right).\left(2x-3\right)=0\)
l) \(3x^3-27x=0\)
tìm GTNN hay GTLN của các đa thức sau:
A=2x2-8x-10
B=9x-3x2
C=2x2+10x-1
D= 2x2-6x
A=2x^2-8x-10
B=9x-3x^2
Tìm GTLN hoặc GTNN
Cứu mik mai nộp
Làm tính chia:
a) (3x4 - 8x3 - 10x2 + 8x - 5) : (3x2 - 2x + 1)
b) (2x3 - 9x2 + 19x - 15) : (x2 - 3x + 5)
1 Tính
a) 3x^2(2x^3 - 3x + 5)
b)(2x - y )^2
2)Phân tích đa thức thành nhân tử
a) 15x^4y^3 - 20x^2y^4
b) 4x^2 - 9x^2
c) x^2 - 3xy + 5x - 15y
b) x^2 - 3x - 10
tim x biết
3x+4=0
2x*(x-1)-(1+2x)=-34
X^2+9x-10=0
(7x-1)*(2+5x)=0
Tìm x biết:
a, 6x(x-3)-2x(3x+1)=-40
b, x2(2x-3)-2x(x2 +3x -1)=5-9x2
c,2(x+5)-x2 - 5x=0
d, x3-5x2 +x-5=0
e, (x-2)(x+1)-(x-1) (x+2)=3
f, 5x(4x+3)-x(20x-3)=36
giúp tớ ạ!
Tìm x : a)(1-3x)2= x (9x-2) b) (x+3)2 - ( 3x3 + 6x2 + 9x ) : 3x = 14
Thu gọn : a)(2x+1)(x-3)-x(x-5)+3x
b)(x-2)3 -x2(x-6)
