Ta đặt:\(A=-1,7-\left|x-2016\right|\)
Xét: \(\left|x-2016\right|\ge0\Rightarrow-1,7-\left|x-2016\right|\ge-1,7\)
Hay A\(\ge\)-1,7. Dấu "=" xảy ra \(\Leftrightarrow\left(x-2016\right)=0\Rightarrow x=2016\)
Vậy \(A\min\limits_{ }=-1,7\Leftrightarrow x=2016\)