Bài 1:
1: \(=x^2-6x+9+2=\left(x-3\right)^2+2>=2\)
Dấu = xảy ra khi x=3
2: \(=2\left(x^2+5x-\dfrac{1}{2}\right)\)
\(=2\left(x^2+5x+\dfrac{25}{4}-\dfrac{27}{4}\right)\)
\(=2\left(x+\dfrac{5}{2}\right)^2-\dfrac{27}{2}>=-\dfrac{27}{2}\)
Dấu = xảy ra khi x=-5/2
3: =-(x^2-5x)
=-(x^2-5x+25/4-25/4)
=-(x-5/2)^2+25/4<=25/4
Dấu = xảy ra khi x=5/2