ĐKXĐ: \(abc\ne0\)
Đặt \(\left(\frac{1}{a};\frac{1}{b};\frac{1}{c}\right)=\left(x;y;z\right)\Rightarrow x+y+z=0\Rightarrow x^3+y^3+z^3=3xyz\)
\(\Rightarrow x^3+y^3+z^3+\frac{3}{4}=0\Leftrightarrow3xyz+\frac{3}{4}=0\)
\(\Leftrightarrow xyz=-\frac{1}{4}\Leftrightarrow\frac{1}{xyz}=-4\Leftrightarrow abc=-4\)
\(\Rightarrow ab=\frac{-4}{c}\Rightarrow c=Ư\left(4\right)=\left\{-4;-2;-1;1;2;4\right\}\)
\(c=-4\Rightarrow ab=1\Rightarrow\left(a;b\right)=\left(1;1\right);\left(-1;-1\right)\)
\(c=-2\Rightarrow ab=2\Rightarrow\left(a;b\right)=\left(1;2\right);\left(2;1\right);\left(-2;-1\right);\left(-1;-2\right)\)
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