16 tháng 8 2022 lúc 10:42
Bài 1: Căn bậc hai
Các câu hỏi tương tự
Bài 1:
a) sqrt{13-2sqrt{42}}
b) sqrt{46+6sqrt{5}}
c) sqrt{12-3sqrt{15}}
d) sqrt{11+sqrt{96}}
Bài 2:
a) Asqrt{6+2sqrt{2}sqrt{3-sqrt{4+2sqrt{3}}}}
b) Bsqrt{5}-sqrt{3-sqrt{29-12sqrt{5}}}
c) Csqrt{3-sqrt{5}}left(sqrt{10}+sqrt{2}right)left(3+sqrt{5}right)
d) Dsqrt{4+sqrt{7}}-sqrt{4-sqrt{7}}
e) Esqrt{8+2sqrt{10+2sqrt{5}}}+sqrt{8-2sqrt{10+2sqrt{5}}}
g) Gsqrt{x+2sqrt{x-1}}+sqrt{x-2sqrt{x-1}}
h) H4x-sqrt{9x^2-12x+4}
i) frac{sqrt{7}-sqrt{2}}{sqrt{7}+sqrt{2}}+frac{sqrt{7}+sqrt{2}}{sqrt{7}-sqrt...
Đọc tiếp
Bài 1:
a) \(\sqrt{13-2\sqrt{42}}\)
b) \(\sqrt{46+6\sqrt{5}}\)
c) \(\sqrt{12-3\sqrt{15}}\)
d) \(\sqrt{11+\sqrt{96}}\)
Bài 2:
a) \(A=\sqrt{6+2\sqrt{2}\sqrt{3-\sqrt{4+2\sqrt{3}}}}\)
b) \(B=\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)
c) \(C=\sqrt{3-\sqrt{5}}\left(\sqrt{10}+\sqrt{2}\right)\left(3+\sqrt{5}\right)\)
d) \(D=\sqrt{4+\sqrt{7}}-\sqrt{4-\sqrt{7}}\)
e) \(E=\sqrt{8+2\sqrt{10+2\sqrt{5}}}+\sqrt{8-2\sqrt{10+2\sqrt{5}}}\)
g) \(G=\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}\)
h) \(H=4x-\sqrt{9x^2-12x+4}\)
i) \(\frac{\sqrt{7}-\sqrt{2}}{\sqrt{7}+\sqrt{2}}+\frac{\sqrt{7}+\sqrt{2}}{\sqrt{7}-\sqrt{2}}\)
Tính GTBT chứa căn:
a,dfrac{2}{4-3sqrt{2}}-dfrac{2}{4+3sqrt{2}}
b,dfrac{2}{1+sqrt{2}}+dfrac{2}{1-sqrt{2}}
c,left(sqrt{14}-3sqrt{2}right)^2+6sqrt{28}
d,left(sqrt{28}-2sqrt{14}+sqrt{7}right).sqrt{7}+7sqrt{8}
e,left(sqrt{6}-sqrt{5}right)^2-2sqrt{120}
Đọc tiếp
Tính GTBT chứa căn:
a,\(\dfrac{2}{4-3\sqrt{2}}\)-\(\dfrac{2}{4+3\sqrt{2}}\)
b,\(\dfrac{2}{1+\sqrt{2}}\)+\(\dfrac{2}{1-\sqrt{2}}\)
c,\(\left(\sqrt{14}-3\sqrt{2}\right)^2+6\sqrt{28}\)
d,\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right).\sqrt{7}+7\sqrt{8}\)
e,\(\left(\sqrt{6}-\sqrt{5}\right)^2-2\sqrt{120}\)
Tính \(\left(\sqrt{7}+\sqrt{11}+\sqrt{13}\right)\left(\sqrt{11}+\sqrt{13}-\sqrt{7}\right)\left(\sqrt{7}+\sqrt{13}-\sqrt{11}\right)\left(\sqrt{7}+\sqrt{11}-\sqrt{13}\right)\)
1.Tính :
a.\(\sqrt{11+6\sqrt{2}}+\sqrt{19+6\sqrt{2}}\)
b.\(-\sqrt{2\left(2-\sqrt{3}\right)}+\sqrt{2\left(2+\sqrt{3}\right)}\)
c.\(\frac{\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}}{2\sqrt{3}}\)
1.Tính:
a.\(\sqrt{11+6\sqrt{2}-\sqrt{19+6\sqrt{2}}}\)
b.\(-\sqrt{2\left(2-\sqrt{3}\right)}+\sqrt{2\left(2+\sqrt{3}\right)}\)
c.\(\frac{\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}}{2\sqrt{3}}\)
tính
a/ (sqrt{2006}- sqrt{2005}).(sqrt{2006}+ sqrt{2005})
b/ (frac{1}{7-4sqrt{3}}+ frac{2}{7+4sqrt{3}}).(21+4sqrt{3})
c/ 3sqrt{frac{9}{8}}- sqrt{frac{49}{2}}+ sqrt{frac{25}{18}}
d/ ( 5sqrt{28}-2sqrt{63}+3sqrt{112}) : sqrt{7}
e/ left(sqrt{5}+sqrt{3}right)sqrt{8-2sqrt{15}}
f/ (frac{4sqrt{21}-4sqrt{15}-sqrt{14}+sqrt{10}}{4sqrt{6}-2+4sqrt{15}-sqrt{10}}
Đọc tiếp
tính
a/ (\(\sqrt{2006}\)- \(\sqrt{2005}\)).(\(\sqrt{2006}\)+ \(\sqrt{2005}\))
b/ (\(\frac{1}{7-4\sqrt{3}}\)+ \(\frac{2}{7+4\sqrt{3}}\)).(21+4\(\sqrt{3}\))
c/ \(3\sqrt{\frac{9}{8}}\)- \(\sqrt{\frac{49}{2}}\)+ \(\sqrt{\frac{25}{18}}\)
d/ ( \(5\sqrt{28}-2\sqrt{63}+3\sqrt{112}\)) : \(\sqrt{7}\)
e/ \(\left(\sqrt{5}+\sqrt{3}\right)\sqrt{8-2\sqrt{15}}\)
f/ (\(\frac{4\sqrt{21}-4\sqrt{15}-\sqrt{14}+\sqrt{10}}{4\sqrt{6}-2+4\sqrt{15}-\sqrt{10}}\)
tính
a/ (sqrt{2006}- sqrt{2005}).(sqrt{2006}+ sqrt{2005})
b/ (frac{1}{7-4sqrt{3}}+ frac{2}{7+4sqrt{3}}).(21+4sqrt{3})
c/ 3sqrt{frac{9}{8}}- sqrt{frac{49}{2}}+ sqrt{frac{25}{18}}
d/ ( 5sqrt{28}-2sqrt{63}+3sqrt{112}) : sqrt{7}
e/ left(sqrt{5}+sqrt{3}right)sqrt{8-2sqrt{15}}
f/ (frac{4sqrt{21}-4sqrt{15}-sqrt{14}+sqrt{10}}{4sqrt{6}-2+4sqrt{15}-sqrt{10}}
Đọc tiếp
tính
a/ (\(\sqrt{2006}\)- \(\sqrt{2005}\)).(\(\sqrt{2006}\)+ \(\sqrt{2005}\))
b/ (\(\frac{1}{7-4\sqrt{3}}\)+ \(\frac{2}{7+4\sqrt{3}}\)).(21+4\(\sqrt{3}\))
c/ \(3\sqrt{\frac{9}{8}}\)- \(\sqrt{\frac{49}{2}}\)+ \(\sqrt{\frac{25}{18}}\)
d/ ( \(5\sqrt{28}-2\sqrt{63}+3\sqrt{112}\)) : \(\sqrt{7}\)
e/ \(\left(\sqrt{5}+\sqrt{3}\right)\sqrt{8-2\sqrt{15}}\)
f/ (\(\frac{4\sqrt{21}-4\sqrt{15}-\sqrt{14}+\sqrt{10}}{4\sqrt{6}-2+4\sqrt{15}-\sqrt{10}}\)
Bài 1: Thực hiện phép tính:
a) \(\sqrt{\sqrt{28+16\sqrt{3}}}\)
b) \(\sqrt{7+4\sqrt{3}}\)
c) \(\sqrt{\sqrt{56-24\sqrt{5}}}\)
d) \(\sqrt{12-2\sqrt{11}}\)
e) \(\sqrt{9+4\sqrt{2}}\)
Mọi người giúp e vs ạ, hứa sẽ tick, e cảm ơn!!
Tính :
A=\(\frac{\sqrt{\sqrt{7}-\sqrt{3}}-\sqrt{\sqrt{7}+\sqrt{3}}}{\sqrt{\sqrt{7}}-2}\)
B= \(\sqrt{6+2\sqrt{2}-\sqrt{3}-\sqrt{4+2\sqrt{3}}}\)
\(\sqrt{ }\)9+2[(\(\sqrt{ }\)28-7\(\sqrt{ }\)7)-(\(\sqrt{ }\)28+7\(\sqrt{ }\)7)]