Question

Thực hiện phép tính :

Q=\(\sqrt{1+2006^2+\dfrac{2006^2}{2007^2}}+\dfrac{2006}{2007}\)

Giúp mình với !

Answer 1

\(Q=\sqrt{1+2006^2+\left(\dfrac{2006}{2007}\right)^2}+\dfrac{2006}{2007}\)  

   =\(1+2006+\dfrac{2006}{2007}+\dfrac{2006}{2007}\)

   =\(2007+\dfrac{4012}{2007}\)

   =\(\dfrac{2007^2}{2007}+4012\)

   =\(\dfrac{4028049}{2007}+\dfrac{4012}{2007}\)

  =\(\dfrac{4032061}{2007}\)

 

Answer 2

\(Q=\sqrt{1+2006^2+\dfrac{2006^2}{2007^2}}+\dfrac{2006}{2007}\)

\(=1+2006+\dfrac{2006}{2007}+\dfrac{2006}{2007}\)

\(=\dfrac{4032061}{2007}\)