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Violympic toán 9
Các câu hỏi tương tự
Cho \(x=\dfrac{\sqrt[3]{26+15\sqrt{3}}.\left(2-\sqrt{3}\right)}{\sqrt[3]{9+\sqrt{80}}+\sqrt[3]{9-\sqrt{80}}}\). Tính giá trị của biểu thức: \(M=\left(3x^3-x^2-1\right)^{2021}\)
Cho A = \(\frac{2x+15\sqrt{x}+18}{x+3\sqrt{x}-18}+\frac{3x+4\sqrt{x}+1}{2x-3\sqrt{x}-5}-\frac{8x-15\sqrt{x}}{2x\sqrt{x}-11x+5\sqrt{x}}\)
Tính A tại \(x=\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\)
Thực hiện phép tính
a) Aleft(dfrac{dfrac{4}{15}+dfrac{4}{35}+dfrac{4}{63}+.......+dfrac{4}{399}}{dfrac{3^2}{8.11}+dfrac{3^2}{11.14}+dfrac{3^2}{14.17}+.....+dfrac{3^2}{197.200}}right).dfrac{200720072007}{200820082008}
b) B1.sqrt{2}+2.sqrt{3}+3.sqrt{4}+....+9sqrt{10}
c) D dfrac{2006}{0,20072008...}+dfrac{2007}{0,020072008...}+dfrac{2008}{0,0020072008}
Đọc tiếp
Thực hiện phép tính
a) A=\(\left(\dfrac{\dfrac{4}{15}+\dfrac{4}{35}+\dfrac{4}{63}+.......+\dfrac{4}{399}}{\dfrac{3^2}{8.11}+\dfrac{3^2}{11.14}+\dfrac{3^2}{14.17}+.....+\dfrac{3^2}{197.200}}\right).\dfrac{200720072007}{200820082008}\)
b) B=\(1.\sqrt{2}+2.\sqrt{3}+3.\sqrt{4}+....+9\sqrt{10}\)
c) D = \(\dfrac{2006}{0,20072008...}+\dfrac{2007}{0,020072008...}+\dfrac{2008}{0,0020072008}\)
thực hiện phép tính
\(\left(\dfrac{15}{\sqrt{6}+1}+\dfrac{4}{\sqrt{16}-2}-\dfrac{12}{3-\sqrt{16}}\right).\left(\sqrt{6}+11\right)\)
Cho \(x=\sqrt{\dfrac{1}{2\sqrt{3}-2}-\dfrac{3}{2.\left(\sqrt{3}+1\right)}}\). Tính: \(A=\dfrac{4.\left(x+1\right).x^{2013}-2.x^{2012}+2x+1}{2x^2+3x}\)
\(\dfrac{6-2\sqrt{3}}{\sqrt{3}-1}-\dfrac{2}{\sqrt{5}+\sqrt{3}}-\sqrt{17+4\sqrt{15}}\)
Giải các phương trình sau:
1.
a. sqrt{x+3}-sqrt{x-4}1
b. sqrt{10-x}+sqrt{x+3}5
c. sqrt{15-x}+sqrt{3-x}6
d. sqrt{x-1}+sqrt{x+1}2
e. sqrt{4x+1}-sqrt{3x+4}1
f. sqrt{x-2sqrt{x-1}}-sqrt{x-1}1
g. sqrt{x+sqrt{2x+1}}+sqrt{x-sqrt{2x-1}}sqrt{2}
h. sqrt{x+sqrt{6x-9}}+sqrt{x-sqrt{6x-9}}sqrt{6}
i. sqrt{x^2-4x+4}+sqrt{x^2-6x+9}1
k. sqrt{x+4-4sqrt{x}}+sqrt{x+9-6sqrt{x}}1
l. sqrt{x+6-4sqrt{x+2}}+sqrt{x+11-6sqrt{x+2}}1
m. sqrt{x+2-4sqrt{x-2}}+sqrt{x+7-6sqrt{x-2}1}
n. sqrt{x}+sqrt{x+sqrt{1-x}}1
o...
Đọc tiếp
Giải các phương trình sau:
1.
a. \(\sqrt{x+3}-\sqrt{x-4}=1\)
b. \(\sqrt{10-x}+\sqrt{x+3}=5\)
c. \(\sqrt{15-x}+\sqrt{3-x}=6\)
d. \(\sqrt{x-1}+\sqrt{x+1}=2\)
e. \(\sqrt{4x+1}-\sqrt{3x+4}=1\)
f. \(\sqrt{x-2\sqrt{x-1}}-\sqrt{x-1}=1\)
g. \(\sqrt{x+\sqrt{2x+1}}+\sqrt{x-\sqrt{2x-1}}=\sqrt{2}\)
h. \(\sqrt{x+\sqrt{6x-9}}+\sqrt{x-\sqrt{6x-9}}=\sqrt{6}\)
i. \(\sqrt{x^2-4x+4}+\sqrt{x^2-6x+9}=1\)
k. \(\sqrt{x+4-4\sqrt{x}}+\sqrt{x+9-6\sqrt{x}}=1\)
l. \(\sqrt{x+6-4\sqrt{x+2}}+\sqrt{x+11-6\sqrt{x+2}}=1\)
m. \(\sqrt{x+2-4\sqrt{x-2}}+\sqrt{x+7-6\sqrt{x-2}=1}\)
n. \(\sqrt{x}+\sqrt{x+\sqrt{1-x}}=1\)
o. \(\sqrt{1-\sqrt{x^2-x}}=\sqrt{x}-1\)
p. \(\sqrt{x^2+6}=x-2\sqrt{x^2-1}\)
q. \(\sqrt{2x^2+8x+6}+\sqrt{x^2-1}=2x+2\)
r. \(\sqrt{x-7}+\sqrt{9-x}=x^2-16x+66\)
s. \(\sqrt{2x-1}+\sqrt{x-2}=\sqrt{x+1}\)
t. \(\sqrt{3x+15}-\sqrt{4x-17}=\sqrt{x+2}\)
u. \(\sqrt{x-1}+\sqrt{x+3}+2\sqrt{\left(x-1\right)\left(x^2-3x+5\right)}=4-2x\)
v. \(\sqrt{x+1}+\sqrt{x+10}=\sqrt{x+2}+\sqrt{x+5}\)
w. \(\sqrt{2x+3+\sqrt{x+2}}+\sqrt{2x+2-\sqrt{x+2}}=1+2\sqrt{x+2}\)
x. \(\sqrt{2x^2-9x+4}+3\sqrt{2x-1}=\sqrt{2x^2+21x-11}\)
y. \(\sqrt{1-x}+\sqrt{x^2-3x+2}+\left(x-2\right)\sqrt{\dfrac{x-1}{x-2}}=3\)
z. \(\left(x-2\right)\left(x+2\right)+4\left(x-2\right)\sqrt{\dfrac{x+2}{x-2}}=-3\)
2.
a. \(\dfrac{2+\sqrt{x}}{\sqrt{2}+\sqrt{2+\sqrt{x}}}+\dfrac{2-\sqrt{x}}{\sqrt{2}-\sqrt{2-\sqrt{x}}}=\sqrt{2}\)
b. \(\dfrac{x}{2+\dfrac{x}{2+\dfrac{x}{2+\dfrac{...}{2+\dfrac{x}{1+\sqrt{1+x}}}}}}=8\) (vế trái có 100 dấu phân thức)
c. \(\sqrt[3]{x+1}+\sqrt[3]{7-x}=2\)
d. \(\sqrt[4]{1-x}+\sqrt[4]{2-x}=\sqrt[4]{3-2x}\)
e. \(\sqrt[4]{1-x^2}+\sqrt[4]{1+x}+\sqrt[4]{1-x}=3\)
f. \(\dfrac{\sqrt[3]{7-x}-\sqrt[3]{x-5}}{\sqrt[3]{7-x}+\sqrt[3]{x-5}}=6-x\)
g. \(\sqrt[3]{x+1}+\sqrt[3]{x+2}+\sqrt[3]{x+3}=0\)
h. \(\sqrt[3]{\left(x+1\right)^2}+\sqrt[3]{\left(x-1\right)^2}+\sqrt[3]{x^2-1}=1\)
i. \(\sqrt[3]{x+1}+\sqrt[3]{x-1}=\sqrt[3]{5x}\)
k. \(\sqrt[3]{x-2}+\sqrt{x+1}=3\)
l. \(\sqrt[3]{24+x}+\sqrt{12-x}=6\)
m. \(\sqrt[3]{2-x}+\sqrt{x-1}=1\)
n. \(1+\sqrt[3]{x-16}=\sqrt[3]{x+3}\)
o. \(\sqrt[3]{25+x}+\sqrt[3]{3-x}=4\)
p. \(\sqrt[3]{x+3}-\sqrt[3]{6-x}=1\)
Làm nhanh giúp mk nhé mn ơi
I . Tìm x để các căn thức sau có nghĩa
a. \(\sqrt{\dfrac{3x-1}{3}}\)
b.\(\sqrt{x^2-2}\)
c.\(\sqrt{\dfrac{7x^2+4}{12}}\)
d.\(\sqrt{\dfrac{3}{2x-15}}\)
e. \(\sqrt{x^2-4x+3}\)
Giải phương trình:
1, \(\dfrac{x^3+5x^2+4x+2}{x^2+2x+3}=\sqrt{x^2+x+2}\)
2, \(\sqrt{x^3+15}+2=\sqrt{x^3+8}+3x\)
3, \(\sqrt{3x+1}-\sqrt{x+3}+1-x=0\)