a. \(\left(xy+1\right)^2-\left(x+y\right)^2=\left(xy+1+x+y\right)\left(xy+1-x-y\right)=\left(x+1\right)\left(y+1\right)\left(x-1\right)\left(y-1\right)\)
b.
thêm bớt 16x^2y^2
\(64x^4+y^4=64x^4+16x^2y^2+y^4-16x^2y^2\)
\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)
\(=\left(8x^2+y^2+4xy\right)\left(8x^2+y^2-4xy\right)\)