d,3x^2+8xy+5y^2=3x^2+3xy+5xy+5y^2=3x(x+y)+5y(x+y)=(x+y)(3x+5y)
e,=(x+2)x^2-2x+4))-(x+2)(x-4)=(x+2)(x^2-3x+8)
\(3x^2+8xy+5y^2\)
= 3x2 + 3xy + 5xy + 5y2
= 3x( x+y) + 5y( x+y)
= (3x+5y)(x+y)
d,3x^2+8xy+5y^2=3x^2+3xy+5xy+5y^2=3x(x+y)+5y(x+y)=(x+y)(3x+5y)
e,=(x+2)x^2-2x+4))-(x+2)(x-4)=(x+2)(x^2-3x+8)