Question

Phân tích thành nhân tử:

x³- 6x²- x+ 30

Answer 1

\(x^3-6x^2-x+30\)

\(=x^3-5x^2-x^2+5x-6x+30\)

\(=x^2\left(x-5\right)+x\left(x-5\right)-6\left(x-5\right)\)

\(=\left(x^2+x-6\right)\left(x-5\right)\)

\(=\left(x^2-3x+2x-6\right)\left(x-5\right)\)

\(=\left(x+2\right)\left(x-3\right)\left(x-5\right)\)

Answer 2

x³- 6x²- x+ 30

=x³+2x²-8x²-16x+15x+30

=(x³+2x²)-(8x²+16x)+(15x+30)

=x²(x+2)-8x(x+2)+15(x+2)

=(x+2)(x²-8x+15)

=(x+2)(x²-3x-5x+15)

=(x+2)[(x²-3x)-(5x-15)]

=(x+2)[x(x-3)-5(x-3)]

=(x+2)(x-3)(x-5)

Answer 3

khó quá,mk k làm đc

Answer 4

mk k làm đc bài nè, vì mk ms lớp 7 thui mà