\(\left(1+2x\right)\left(1-2x\right)-x\left(x+2\right)\left(x-2\right)\)
\(=\left(1-4x^2\right)-x\left(x^2-4\right)\)
\(=1-4x^2-x^3+4x\)
\(=-\left(x^3+4x^2-4x-1\right)\)
\(=-\left(x^3-x^2+5x^2-5x+x-1\right)\)
\(=-\left[x^2\left(x-1\right)+5x\left(x-1\right)+\left(x-1\right)\right]\)
\(=-\left[\left(x-1\right)\left(x^2+5x+1\right)\right]\)
Chúc bạn học tốt!!!
Ta có : $(1+2x)(1-2x)-x(x+2)(x-2)$
$=1-4x^2-x(x^2-4)$
$=1-4x^2-x^3+4x$
$=-x^3-4x^2+4x+1$
$=(-x^3+x^2)-(5x^2-5x)-(x-1)$
$=(x-1).(-x^2)-5x(x-1)-(x-1)$
$=(x-1)(-x^2-5x-1)$