Question

Phân tích đa thức thành nhân tử:

a) x⁴+3x³+x+3

b) 64-x² -y²-2xy

Answer 1

a) x⁴ + 3x³ + x + 3

= (x⁴ + 3x³) + (x + 3)

= x³(x + 3) + (x + 3)

= (x + 3)(x² + 1)

b) 64 - x² - y² - 2xy

= 64 - (x² + 2xy + y²)

= 8² - (x + y)²

= (8 - x - y)(8 + x + y)

Answer 2

a) x⁴ + 3x³ + x + 3

= (x⁴ + 3x³) + (x + 3)

= x³(x + 3) + (x + 3)

= (x + 3)(x² + 1)

b) 64 - x² - y² - 2xy

= 64 - (x² + 2xy + y²)

= 8² - (x + y)²

= (8 - x - y)(8 + x + y)

Answer 3

a)x⁴+3x³+x+3

=(x⁴+3x³)+(x+3)

=x³(x+3)+(x+3)

=(x+3)(x³+1)

b)64-x²-y²-2xy

=64-(x²+2xy+y²)

=8²-(x+y)²

=(8+x-y)(8-x-y)

Answer 4

a)x⁴+3x³+x+3

 

=(x⁴+3x³)+(x+3)

 

=x³(x+3)+(x+3)

 

=(x+3)(x³+1)

 

b)64-x²-y²-2xy

 

=64-(x²+2xy+y²)

 

=8²-(x+y)²

 

=(8+x+y)(8-x-y)