Question

phan tích đa thức thành nhân tử

a) x^2 -6

b) x^2 + 2 căn 3 x + 3

c) x^2 -2 căn 5 x + 5 

Answer 1

Đây nè bạn.

Answer 2

a, \(x^2-6=x^2-\sqrt{6^2}=\left(x-\sqrt{6}\right)\left(x+\sqrt{6}\right)\)

b, \(x^2+2\sqrt{3}x+3=x^2+2\sqrt{3}x+\sqrt{3}=\left(x+\sqrt{3}\right)^2=\left(x+\sqrt{3}\right)\left(x+\sqrt{3}\right)\)

c, \(x^2-2\sqrt{5}x+5=x^2-2\sqrt{5}x+\sqrt{5}=\left(x-\sqrt{5}\right)^2=\left(x-\sqrt{5}\right)\left(x-\sqrt{5}\right)\)

Answer 3

a: \(x^2-6=\left(x-\sqrt{6}\right)\left(x+\sqrt{6}\right)\)

b: \(x^2+2\sqrt{3}x+3=\left(x+\sqrt{3}\right)^2\)

c: \(x^2-2\sqrt{5}x+5=\left(x-\sqrt{5}\right)^2\)