Question

phân tích đa thức thành nhân tử
81x²y - 27xy²

2x^{3 +} 4x² - 6x

25x² - 10xy + 30xy²

27x³ -36xy 

15x² + 30xy + 25xy²

giúp mình với 

Answer 1

\(81x^2y-27xy^2=27xy\left(3x-y\right)\)

\(2x^3+4x^2-6x=2x\left(x^2+2x-3\right)=2x\left(x+3\right)\left(x-1\right)\)

\(25x^2-10xy+30xy^2=5x\left(5x-2y+6y^2\right)\)

\(27x^3-36xy=9x\left(3x^2-4y\right)\)

\(15x^2+30xy+25xy^2=5x\left(3x+6y+5y^2\right)\)

Answer 2

\(81x^2y-27xy^2==27xy\left(3x-y\right);2x^3+4x^2-6x=2x\left(x^2+2x-3\right)=2x\left(x+3\right)\left(x-1\right);25x^2-10xy+30xy^2=5x\left(5x-2y+6y^2\right);27x^3-36xy=3x\left(9x^2-12y\right);15x^2+30xy+25xy^2=5x\left(3x+6y+5y^2\right)\)