Question

Phân tích đa thức thành nhân tử

\(x^3-6x^2+18x-27\)

Answer 1

= (x³ - 27) - (6x² - 18x)

= (x³ - 3³) - 6x(x - 3)

= (x-3)(x²+3x+3²) - 6x(x-3)

= (x-3)(x²+3x+9-6x)

= (x-3)(x²-3x+9)

Answer 2

ta có : \(x^3-6x^2+18x-27=x^3-3x^2-3x^2+9x+9x-27\)

\(=x^2\left(x-3\right)-3x\left(x-3\right)+9\left(x-3\right)=\left(x-3\right)\left(x^2-3x+9\right)\)

Answer 3

x3-6x2+18x-27

= (x3 - 27) - (6x2 - 18x)

= (x3 - 33) - 6x(x - 3)

= (x-3)(x2+3x+32) - 6x(x-3)

= (x-3)(x2+3x+9-6x)

= (x-3)(x2-3x+9)