Question

Phân tích đa thức thành nhân tử : (a² + b² + 2)² - 4(ab -1)²

Answer 1

(b+a)^2*(b^2-2*a*b+a^2+4)

Answer 2

\(=\left[a^2+b^2+2-2\left(ab-1\right)\right]\left[a^2+b^2+2+2\left(ab-1\right)\right]\\ =\left(a^2+b^2-2ab+4\right)\left(a^2+b^2+2ab\right)\\ =\left(a+b\right)^2\left(a^2+b^2-2ab+4\right)\)

Answer 3

\(\left(a^2+b^2+2\right)^2-\left(2ab-2\right)^2\)

\(=\left(a^2+b^2+2-2ab+2\right)\left(a^2+b^2+2+2ab-2\right)\)

\(=\left(a^2+b^2-2ab+4\right)\left(a+b\right)^2\)

Answer 4

${}^{}-{}^{}$

$=\left({}^{}+{}^{}+2-2ab+2\right)\left({}^{}+{}^{}+2+2ab-2\right)$

$=\left({}^{}+{}^{}-2ab+4\right){}^{}$