Question

Phân tích đa thức thành nhân tử : 2x² + x – 6 

Answer 1

\(2x^2+x-6\)

\(=2x^2-3x+4x-6\)

\(=x\left(2x-3\right)+2\left(2x-3\right)\)

\(=\left(2x-3\right)\left(x+2\right)\)

Answer 2

Tham Khảo

Answer 3

2x² + x - 6

= 2x² + 4x - 3x - 6

= 2x(x + 2) - 3(x - 2)

= (2x - 3)(x + 2)

Answer 4

\(2x^2+x-6\\ =2x^2+4x-3x-6\\ =\left(2x^2+4x\right)-\left(3x+6\right)\\ =2x\left(x+2\right)-3\left(x+2\right)\\ =\left(x+2\right)\left(2x-3\right)\)

Answer 5

=2 + 4x- 3x – 6

= (2 + 4x) – (3x +6)

= 2x. (x+2) – 3.(x+2)

= (x+2).(2x-3)

Answer 6

\(2x^2+x-6\)

\(=2x^2+4x-3x-6\)

\(=\left(x+2\right)\left(2x-3\right)\)