Question

Phân tích đa thức sau thành nhân tử:

\(^{x^2+2x+1-4x^2}\)

Answer 1

\(x^2+2x+1-4x^2\)

\(=\left(x+1\right)^2-\left(2x\right)^2=\left(x+1-2x\right)\left(x+2x+1\right)\)

Answer 2

\(x^2+2x+1-4x^2=\left(x+1\right)^2-\left(2x\right)^2=\left(x+1+2x\right)\left(x+1-2x\right)=\left(3x+1\right)\left(1-x\right)\)