Question

Phân tích đa thức sau thành nhân tử

\(2x.\left(y-1\right)-2y.\left(y-1\right)\)

\(10xy.\left(x-y\right)-6y.\left(y-x\right)\)

Answer 1

a) \(2x\left(y-1\right)-2y\left(y-1\right)=2\left(x-y\right)\left(y-1\right)\)

b) \(10xy\left(x-y\right)-6y\left(y-x\right)=\left(10xy+6y\right)\left(x-y\right)\) \(2y\left(5x+3\right)\left(x-y\right)\)

Answer 2

a) Ta có: \(2x\left(y-1\right)-2y\left(y-1\right)\)

\(=2x\cdot\left(y-1\right)-2y\cdot\left(y-1\right)\)

\(=\left(y-1\right)\cdot\left(2x-2y\right)\)

\(=2\cdot\left(y-1\right)\cdot\left(x-y\right)\)

b) Ta có: \(10xy\cdot\left(x-y\right)-6y\cdot\left(y-x\right)\)

\(=10xy\cdot\left(x-y\right)+6y\cdot\left(x-y\right)\)

\(=\left(x-y\right)\left(10xy+6y\right)\)

\(=2y\cdot\left(x-y\right)\cdot\left(5x+3\right)\)