\(\left(2x^2+3\right)^2-10x^3-15x=0\)
\(\Rightarrow\left(2x^2+3\right)^2-5x\left(2x^2+3\right)=0\)
\(\Rightarrow\left(2x^2+3\right)\left(2x^2+3-5x\right)=0\)
\(2x^2+3>0\Rightarrow2x^2-5x+3=0\)
\(\Rightarrow2x\left(x-1\right)-3\left(x-1\right)=0\Leftrightarrow\left(2x-3\right)\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=1\\x=\frac{3}{2}\end{matrix}\right.\)Vậy nghiệm lớn nhất x=3/2