Question

Nếu a chia cho 11 dư 4 thì a^2 chia cho 11 dư bao nhêu

Answer 1

Đặt \(a=11x+4\)

\(a^2=\left(11x+4\right)^2=121x^2+88x+16\)

\(=121x^2+88x+11+5\)

\(=11\left(11x^2+8x+1\right)+5\)

\(\Rightarrow a^2\) chia 11 dư 5

Vậy...

Answer 2

a chia 11 dư 4 => a có dạng 11k + 4

$=>a^2=(11k+4)^2=121k^2+88k+16=11(11k^2+8k+1)+5$

$=>a^2$ chia 11 dư 5.

Answer 3

Đặt \(a=11x+4\)

\(a^2=\left(11x+4\right)^2=121x^2-88x+16\)

\(=121x^2+88x+11+5\)

\(=11\left(11x^2+8x+1\right)+5\)

\(=a^2\) chia 11 dư 5

Vậy \(a^2\) chia 11 dư 5