Đề là \(log_2x.log_3\left(2x+1\right)=2log_2x\)
Hay \(log2^x.log3^{2x+1}=2log2^x\) hả bạn?
\(log_2x.log_3\left(2x+1\right)=2log_2x\)
\(\Leftrightarrow log_2x\left(log_3\left(2x+1\right)-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}log_2x=0\\log_3\left(2x+1\right)=2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\2x+1=9\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\end{matrix}\right.\)