\(\left|2x-3\right|-x=\left|2-x\right|\)
\(\Leftrightarrow\left|2x-3\right|-x=\left|x-2\right|\)
Trường hợp 1: x<3/2
Phương trình sẽ là 3-2x-x=2-x
=>-3x+3=2-x
=>-2x=-1
hay x=1/2(nhận)
Trường hợp 2: 3/2<=x<2
Pt sẽ là 2x-3-x=2-x
=>x-3=2-x
=>2x=5
hay x=5/2(loại)
Trường hợp 3: x>=2
Pt sẽ là 2x-3-x=x-2
=>x-3=x-2(loại)
1) \(\left|3x+2\right|=\left|x+1\right|\)
2) \(\left|\left(x+2\right)\times x\right|=\left|x+2\right|\)
3) \(\left|2x+3\right|=x+1\)
4) \(\left|4x+5\right|+3.x=7\)
\(5^{\left(x-2\right).\left(x+3\right)}=1\)
\(-\left(x-y\right)^2=\left(y-3\right)^2\)
\(7^{\left(2x-1\right).\left(3x-1\right)}=1\)
4, tìm x biết;
a, \(\left|x-1\right|+\left|x-3\right|=4\)
b. \(\left|2x-1\right|+\left|x+2\right|=3\)
a)\(\left(x-\frac{2}{3}\right)\). \(\left(x+\frac{1}{4}\right)\)= 0
b) \(\left(x-\frac{2}{3}\right)\). \(\left(2x-\frac{3}{4}\right)\) = \(\left(3x+\frac{1}{2}\right)\). \(\left(x+\frac{2}{3}\right)\)
tìm x
a) \(\left|\dfrac{1}{3}x\right|\cdot\left|-2.7\right|=\left|-3\right|\)
b) \(2\left|2x-1\right|+\left|-7\right|=19\)
c) \(\left|x\right|>2\)
d)\(\left|x+a\right|< 2\)
f) \(\left|3x-2\right|\ge4\)
tìm x, biết
a) \(\left|x+2\right|+\left|x-3\right|=7\)
b) \(\left|x+2\right|-6x=1\)
c) \(\left|2x+1\right|+\left|x+8\right|=4x\)
d) \(x+\left|x+2017\right|=-2017\)
Tìm x, biết:
a) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\) ; b) \(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) ; c) |2x-3|+3=16 ; d) \(42+\frac{3}{7}.\left|3x-1\right|=12\)
e) \(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\) ; f) |2x-1|=|x+2| ; g) \(2.3^x.3^2=18\left(x\in N\right)\) ; h) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
Tính GTBT :
A = 2x2 - 3 . \(\left|x\right|\) + 1 với \(\left|x\right|\) = 2
B = 2 . \(\left|x-2\right|\) - 3 . \(\left|1-x\right|\) với x = 4
2. Tìm x biết:
a)2(x+2)(x+4)\dfrac{2}{\left(x+2\right)\left(x+4\right)} + 4(x+4)(x+8)\dfrac{4}{\left(x+4\right)\left(x+8\right)} + 6(x+8)(x+14)\dfrac{6}{\left(x+8\right)\left(x+14\right)} = x(x+2)(x+14)\dfrac{x}{\left(x+2\right)\left(x+14\right)}
b)x2023\dfrac{x}{2023} + x+12022\dfrac{x+1}{2022} x+22021\dfrac{x+2}{2021} +...+ x+20221\dfrac{x+2022}{1} + 2023 = 0.
Gíup mình giải 2 bài này với!
Cảm ơn các bạn rất nhiều!!!
Tìm x
a) \(\left(\dfrac{3}{5}x-\dfrac{2}{3}x-x\right)\cdot\dfrac{1}{7}=-\dfrac{5}{21}8\)
b) \(\left(5x-1\right)\cdot\left(2x+\dfrac{1}{3}\right)=0\)
c) \(\dfrac{5\left|x+1\right|}{2}=\dfrac{90}{\left|x+1\right|}\)
