ĐKXĐ: ...
\(\Leftrightarrow x^3+\left(\frac{x}{x-1}\right)^3+\frac{3x^2}{x-1}\left(x+\frac{x}{x-1}\right)-\frac{3x^2}{x-1}\left(x+\frac{x}{x-1}\right)+\frac{3x^2}{x-1}=9\)
\(\Leftrightarrow\left(x+\frac{x}{x-1}\right)^3-3\left(\frac{x^2}{x-1}\right)^2+\frac{3x^2}{x-1}-1=8\)
\(\Leftrightarrow\left(\frac{x^2}{x-1}\right)^3-3\left(\frac{x^2}{x-1}\right)^2+\frac{3x^2}{x-1}-1=8\)
\(\Leftrightarrow\left(\frac{x^2}{x-1}-1\right)^3=8\)
\(\Leftrightarrow\frac{x^2}{x-1}-1=2\)
\(\Leftrightarrow x^2-3\left(x-1\right)=0\Leftrightarrow x^2-3x+3=0\)
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