\(x=0\) không phải nghiệm, chia 2 vế cho \(x^4\)
\(\Leftrightarrow5-\frac{2}{x^2}-3\sqrt{\frac{1}{x^2}+\frac{2}{x^4}}=\frac{4}{x^4}\)
\(\Leftrightarrow2\left(\frac{2}{x^4}+\frac{1}{x^2}\right)+3\sqrt{\frac{2}{x^4}+\frac{1}{x^2}}-5=0\)
Đặt \(\sqrt{\frac{2}{x^4}+\frac{1}{x^2}}=a>0\)
\(\Rightarrow2a^2+3a-5=0\Rightarrow\left[{}\begin{matrix}a=1\\a=-\frac{5}{2}\left(l\right)\end{matrix}\right.\)
\(\Rightarrow\frac{2}{x^4}+\frac{1}{x^2}=1\Leftrightarrow x^4-x^2-2=0\Rightarrow x=\pm\sqrt{2}\)