(x-3)\(\sqrt{x^2+5}\)=(x-3)(x-\(\dfrac{1}{2}\))
\(\Leftrightarrow\)(x-3)(\(\sqrt{x^2+5}\)-x+\(\dfrac{1}{2}\))=0
\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=3\\\text{}\text{}\sqrt{x^2+5}=x-\dfrac{1}{2}\left(\circledast\right)\end{matrix}\right.\)
Giải ✳, đk:x\(\ge\dfrac{1}{2}\)
x2+5=\(\left(x-\dfrac{1}{2}\right)^2\)
\(\Leftrightarrow x=-\dfrac{19}{4}\)(loại)