\(\Leftrightarrow\left(x-1\right)\left(x-3\right)\left(x+2\right)\left(x-6\right)-34=0\)
\(\Leftrightarrow\left(x^2-4x+3\right)\left(x^2-4x-12\right)-34=0\)
Đặt \(x^2-4x-12=t\)
\(\left(t+15\right)t-34=0\Leftrightarrow t^2+15t-34=0\Rightarrow\left[{}\begin{matrix}t=2\\t=-17\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x^2-4x-12=2\\x^2-4x-12=-17\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x^2-4x-14=0\\x^2-4x+5=0\end{matrix}\right.\)