\(\left(x+2\right):2=\left(5x-8\right):4\)
\(\Leftrightarrow\dfrac{x+2}{2}=\dfrac{5x-8}{4}\)
\(\Leftrightarrow2\left(x+2\right)=5x-8\)
`<=>2x+4=5x-8`
`<=>3x=12`
`<=>x=4`
Vậy `S={4}`
<=> \(\dfrac{x+2}{2}=\dfrac{5x-8}{4}\)
<=> \(\dfrac{2\left(x+2\right)}{4}=\dfrac{5x-8}{4}\)
<=> \(2x+4=5x-8\)
<=> \(2x+4-5x+8=0\)
<=> \(12-3x=0\)
=> 3x = 12
=> x = 4
\(\dfrac{x+2}{2}=\dfrac{5x-8}{4}\\ \Leftrightarrow\dfrac{2\left(x+2\right)}{4}=\dfrac{5x-8}{4}\\ \Leftrightarrow2x+4=5x-8\\ \Leftrightarrow2x-5x=-8-4\\ \Leftrightarrow-3x=-12\\ \Leftrightarrow3x=12\\ \Leftrightarrow x=4\)