\(n_{O2}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
\(PTHH:2Na+O_2\rightarrow2Na_2O\)
TPỨ____0,23 __ 0,1______ (mol)
PỨ____0,2____0,1 _____ 0,2 (mol)
SPỨ____ 0,03____0_____0,2 (mol)
a/ Natri dư
\(m_{Na\left(Pư\right)}=0,03.23=0,69\left(g\right)\)
b/ \(m_{Na2O}=0,2.62=12,4\left(g\right)\)
Gọi tên : Natri Oxit
Phân loại : Oxit Bazơ
a)\(4Na+O2-->2Na2O\)
\(n_{Na}=\frac{0,23}{23}=0,01\left(mol\right)\)
\(n_{O2}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
Lập tỉ lệ
\(n_{Na}\left(\frac{0,01}{4}\right)< n_{O2}\left(\frac{0,1}{1}\right)=>O2dư\)
\(n_{O2}=\frac{1}{4}n_{Na}=0,0025\left(mol\right)\)
\(n_{O2}dư=0,1-0,0025=0,0975\left(mol\right)\)
\(m_{O2}dư=0,0975.32=3,12\left(g\right)\)
b)\(n_{Na2O}=\frac{1}{2}n_{Na}=0,005\left(mol\right)\)
\(m_{Na2O}=0,005.62=0,31\left(g\right)\)
