\(=>2\left(x+2\right)=\left(1-x\right)3\\ =>2x+4=3-3x\\ =>2x+3x=3-4\\ =>5x=-1\\ =>x=-\dfrac{1}{5}\)
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Bài 4: Giá trị tuyệt đối của một số hữu tỉ. Cộng, trừ, nhân, chia số thập phân
Các câu hỏi tương tự
Tìm X, biết
a, X+ \(\dfrac{5}{6}=\dfrac{2}{5}-\dfrac{-2}{3}\)x
b,\(1\dfrac{2}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}-\dfrac{1}{5}x\)
c,\(\dfrac{1}{3}-\dfrac{2}{3}\left(x-\dfrac{1}{2}\right)=1\)
Tìm x biết:
a) left|x-dfrac{1}{2}right|+left|x+2right|dfrac{3}{4}
b) left(dfrac{2}{3}-2xright).1dfrac{1}{2}dfrac{3}{4}
c) left|x-1right|+2left(x+4right)10
d) dfrac{11}{12}+dfrac{11}{12.23}+...+dfrac{11}{89.100}+x1dfrac{2}{3}
e) left(dfrac{2}{11.13}+dfrac{2}{13.15}+...+dfrac{2}{19.21}right)-x+4dfrac{221}{231}2dfrac{1}{3}
Đọc tiếp
Tìm x biết:
a) \(\left|x-\dfrac{1}{2}\right|+\left|x+2\right|=\dfrac{3}{4}\)
b) \(\left(\dfrac{2}{3}-2x\right).1\dfrac{1}{2}=\dfrac{3}{4}\)
c) \(\left|x-1\right|+2\left(x+4\right)=10\)
d) \(\dfrac{11}{12}+\dfrac{11}{12.23}+...+\dfrac{11}{89.100}+x=1\dfrac{2}{3}\)
e) \(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right)-x+4\dfrac{221}{231}=2\dfrac{1}{3}\)
Tìm x , biết :
1, |dfrac{3}{2}x + dfrac{1}{2}| | 4x - 1 |
2, | dfrac{5}{4}x - dfrac{7}{2} | - | dfrac{5}{8}x+dfrac{3}{5} | 0
3, | dfrac{7}{5}x+dfrac{2}{3} | | dfrac{4}{3}x-dfrac{1}{4} |
4, | dfrac{7}{8}x+dfrac{5}{6} | - | dfrac{1}{2}x+5 | 0
Đọc tiếp
Tìm x , biết :
1, |\(\dfrac{3}{2}\)x + \(\dfrac{1}{2}\)| = | 4x - 1 |
2, | \(\dfrac{5}{4}\)x - \(\dfrac{7}{2}\) | - | \(\dfrac{5}{8}x+\dfrac{3}{5}\) | = 0
3, | \(\dfrac{7}{5}x+\dfrac{2}{3}\) | = | \(\dfrac{4}{3}x-\dfrac{1}{4}\) |
4, | \(\dfrac{7}{8}x+\dfrac{5}{6}\) | - | \(\dfrac{1}{2}x+5\) | = 0
tìm giá trị lớn nhất của các biểu thức
\(A=5-3\left(2x-1\right)^2\) \(B=\dfrac{1}{2\cdot\left(x-1\right)^2+3}\) \(C=\dfrac{x^2+8}{x^2+2}\) \(D=\dfrac{1}{\sqrt{x}+3}\)
Câu 1: Tinh
Aleft(dfrac{3}{5}right)^2.5^2-left(2dfrac{1}{4}right)^3:left(dfrac{3}{4}right)^3+dfrac{1}{2}
Bleft[dfrac{4}{11}.left(dfrac{1}{25}right)^0+dfrac{7}{22}.2right]^{2010}-left(dfrac{1}{2^2}:dfrac{8^2}{4^4}right)^{2009}
dfrac{7}{8}.left(dfrac{2}{12}+dfrac{4}{10}right)
dfrac{3}{2}-dfrac{5}{6}:left(dfrac{1}{2}right)^2+sqrt{4}
Câu 2: Tim x
2.x-dfrac{5}{4}dfrac{20}{15}
left(x+dfrac{1}{3}right)^3left(dfrac{-1}{8}right)
Đọc tiếp
Câu 1: Tinh
\(A=\left(\dfrac{3}{5}\right)^2.5^2-\left(2\dfrac{1}{4}\right)^3:\left(\dfrac{3}{4}\right)^3+\dfrac{1}{2}\)
\(B=\left[\dfrac{4}{11}.\left(\dfrac{1}{25}\right)^0+\dfrac{7}{22}.2\right]^{2010}-\left(\dfrac{1}{2^2}:\dfrac{8^2}{4^4}\right)^{2009}\)
\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)
\(\dfrac{3}{2}-\dfrac{5}{6}:\left(\dfrac{1}{2}\right)^2+\sqrt{4}\)
Câu 2: Tim x
\(2.x-\dfrac{5}{4}=\dfrac{20}{15}\)
\(\left(x+\dfrac{1}{3}\right)^3=\left(\dfrac{-1}{8}\right)\)
Tìm x :
2|x+\(3\dfrac{1}{2}\)|+|x|-\(3\dfrac{1}{2}\)=|\(2\dfrac{1}{5}\)-x|
1, \(\dfrac{x}{3}=\dfrac{y}{2}\); \(\dfrac{x}{5}=\dfrac{x}{7}\) và x +2y = -112
2, 2x = 3y; 5y = 7z và 3x - 7y + 5z = 30
3, \(\dfrac{x}{y}=\dfrac{10}{9};\) \(\dfrac{y}{z}=\dfrac{3}{4}\) và x +2y - 3z = -48
Làm giúp, cần gấp
Tìm \(x\)\(\in\)\(Q\):
\(a\)\()\) \(|0,5.x-2|-|x+\dfrac{2}{3}|=0\)
\(b)\) \(2x-|x+1|=\dfrac{-1}{2}\)
a,dfrac{x}{48}dfrac{-4}{7} b,(x+dfrac{4}{5})-dfrac{2}{5}dfrac{3}{5} c, 2|x-1|^272 d,dfrac{1}{6}x-dfrac{2}{3}2 e,dfrac{x}{2,5}dfrac{4}{5}
f,|x-2|-41
Đọc tiếp
a,\(\dfrac{x}{48}\)=\(\dfrac{-4}{7}\) b,(x+\(\dfrac{4}{5}\))-\(\dfrac{2}{5}\)=\(\dfrac{3}{5}\) c, 2\(|\)x-1\(|\)\(^2\)=72 d,\(\dfrac{1}{6}\)x-\(\dfrac{2}{3}\)=2 e,\(\dfrac{x}{2,5}\)=\(\dfrac{4}{5}\)
f,\(|x-2|-4=1\)
\(\left|\dfrac{1}{2}x-\dfrac{1}{6}\right|=\dfrac{1}{3}\)