2, \(\Rightarrow\left\{{}\begin{matrix}\\\dfrac{5}{4}x-\dfrac{7}{2}=0\\\dfrac{5}{8}x+\dfrac{3}{5}=0\\\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{14}{5}\\\\x=\dfrac{-24}{25}\\\end{matrix}\right.\)
2, \(\Rightarrow\left\{{}\begin{matrix}\\\dfrac{5}{4}x-\dfrac{7}{2}=0\\\dfrac{5}{8}x+\dfrac{3}{5}=0\\\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{14}{5}\\\\x=\dfrac{-24}{25}\\\end{matrix}\right.\)
Câu 1: Tinh
\(A=\left(\dfrac{3}{5}\right)^2.5^2-\left(2\dfrac{1}{4}\right)^3:\left(\dfrac{3}{4}\right)^3+\dfrac{1}{2}\)
\(B=\left[\dfrac{4}{11}.\left(\dfrac{1}{25}\right)^0+\dfrac{7}{22}.2\right]^{2010}-\left(\dfrac{1}{2^2}:\dfrac{8^2}{4^4}\right)^{2009}\)
\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)
\(\dfrac{3}{2}-\dfrac{5}{6}:\left(\dfrac{1}{2}\right)^2+\sqrt{4}\)
Câu 2: Tim x
\(2.x-\dfrac{5}{4}=\dfrac{20}{15}\)
\(\left(x+\dfrac{1}{3}\right)^3=\left(\dfrac{-1}{8}\right)\)
Tìm X, biết
a, X+ \(\dfrac{5}{6}=\dfrac{2}{5}-\dfrac{-2}{3}\)x
b,\(1\dfrac{2}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}-\dfrac{1}{5}x\)
c,\(\dfrac{1}{3}-\dfrac{2}{3}\left(x-\dfrac{1}{2}\right)=1\)
Tìm x biết :
b) |x - 1| + 3x = 1
c) |2x - 1| = |2x + 3|
d) |x| + |x + 2| = 0
e) \(\left|x\left(x^2-\dfrac{5}{4}\right)\right|=x\)
Tìm x biết x thuộc Z
a) |x| < \(2\dfrac{4}{5}\)
b) |x| > \(11\dfrac{3}{8}\)
c) \(\left|x-\dfrac{5}{3}\right|< \dfrac{1}{3}\)
d) \(\left|x+\dfrac{11}{2}\right|>\left|-5,5\right|\)
e) \(\dfrac{7}{6}< \left|x-\dfrac{2}{3}\right|< \dfrac{26}{9}\)
f) \(\dfrac{2}{5}< \left|x-\dfrac{7}{5}\right|< \dfrac{3}{5}\)
Bất kì câu trả lời nào liên quan đến câu hỏi tớ đều tick nhé, nhưng nếu có bạn làm rồi mà một bạn khác làm lại thì tớ không tick
a) 6.5 - \(\dfrac{9}{4}\): / x+ \(\dfrac{1}{3}\)/=2
b)\(\dfrac{11}{4}\)+\(\dfrac{2}{3}\):/4x - \(\dfrac{1}{5}\) / =\(\dfrac{7}{2}\)
c) (x-\(\dfrac{1}{4}\))2 + / 2x - \(\dfrac{1}{2}\)= 0
a,\(\dfrac{x}{48}\)=\(\dfrac{-4}{7}\) b,(x+\(\dfrac{4}{5}\))-\(\dfrac{2}{5}\)=\(\dfrac{3}{5}\) c, 2\(|\)x-1\(|\)\(^2\)=72 d,\(\dfrac{1}{6}\)x-\(\dfrac{2}{3}\)=2 e,\(\dfrac{x}{2,5}\)=\(\dfrac{4}{5}\)
f,\(|x-2|-4=1\)
1, \(\dfrac{x}{3}=\dfrac{y}{2}\); \(\dfrac{x}{5}=\dfrac{x}{7}\) và x +2y = -112
2, 2x = 3y; 5y = 7z và 3x - 7y + 5z = 30
3, \(\dfrac{x}{y}=\dfrac{10}{9};\) \(\dfrac{y}{z}=\dfrac{3}{4}\) và x +2y - 3z = -48
Làm giúp, cần gấp
Tìm x biết: \(\left|x-\dfrac{1}{3}\right|\)+\(\dfrac{4}{5}\)\(=\left|-3,2+\dfrac{2}{5}\right|\)
Tìm GTNN của biểu thức sau:
a. B = \(\left|x+\dfrac{1}{2}\right|+\left|x+\dfrac{1}{3}\right|+\left|x+\dfrac{1}{4}\right|\)
b. \(C=3\left|x+-\dfrac{2}{5}\right|+\dfrac{5}{7}\)
Giúp với!
Tìm x, biết:
a) \(\dfrac{x+1}{5}\) + \(\dfrac{x+3}{4}\) = \(\dfrac{x+5}{3}\) + \(\dfrac{x+7}{2}\)
b) \(\dfrac{3}{\left(x+2\right)\left(x+5\right)}\) + \(\dfrac{5}{\left(x+5\right)\left(x+10\right)}\) + \(\dfrac{7}{\left(x+10\right)\left(x+17\right)}\) = \(\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
Giải chi tiết cho mk cả hai phần nha!