Vì \(x^2+\text{3}x+10=\left(x+\dfrac{\text{3}}{2}\right)^2+\dfrac{\text{3}1}{4}>0\) nên phân thức XĐ với mọi x.
\(PT\Leftrightarrow x^2-4=0\\ \Leftrightarrow x=\pm2\\ S=\left\{\pm2\right\}\)
Vì \(x^2+\text{3}x+10=\left(x+\dfrac{\text{3}}{2}\right)^2+\dfrac{\text{3}1}{4}>0\) nên phân thức XĐ với mọi x.
\(PT\Leftrightarrow x^2-4=0\\ \Leftrightarrow x=\pm2\\ S=\left\{\pm2\right\}\)
1) (x2-4x+16) (x+4)-x(x+1) (x+2)+3x2=0
2) (8x+2) (1-3x)+(6x-1) (4x-10)=-50
3) (x2+2x+4) (2-x)+x(x-3) (x+4)-x2+24=0
4) (\(\dfrac{x}{2}\)x2+3) (5-6x)+(12x-2) (\(\dfrac{x}{4}\)x4+3)=0
1) 5(x-3) (x-7)-(5x+1) (x-2)= -8
2) x(x+1) (x+2)-(x+4) (3x-5)= 84-5x
3) (9x2-5) (x+3)-3x2(3x+9)=(x-5) (x+4)-x(x-11)
4) (x2-4x+16) (x+4)-x(x+1) (x+2)+3x2=0
5) (8x+2) (1-3x)+(6x-1) (4x-10)=-50
6) (x2+2x+4) (2-x)+x(x-3) (x+4)-x2+24=0
7) (\(\dfrac{x}{2}\)+3) (5-6x)+(12x-2) (\(\dfrac{x}{4}\)+3)=0
Bài 1:
a) x (\(x^2\) + 2) + 2x\((1-\dfrac{1}{2}x^2)=4\)
b) (2x)\(^2\) (x – 1) + x(\(x^2\) + 4x) = 40
c) 3x(x – 2) – 3(\(x^2\) – 3) = 8
d) 2\(x^2\)(4\(x^3\) + 2x) + (\(x^2\) – 2)(- 2x)\(^3\) = 20
Bài 2:
P = 3x(\(\dfrac{2}{3}\)\(x^2\) − \(3x^4)\) + (3x)\(^2\) (\(x^3\) – 1) + (- 2x + 9)\(x^2\) - 12
Tìm x:
1/3x(\(-\dfrac{4}{3}\)x+1)-4x(x-2)=10
2/5(x2-3x+1)+x(1-5x)=x-2
3/12x2-4x(3x-5)=10x-17
4/4x2-2x+3-4x(x-5)=7x-3
5/-3(x-5)+5(x-1)+3x2=4-x
1. (2x +3) (x- 5) +(X-4 ) + (x-5) ( x-2 0 = (3x -5) ( x-4)
2. (8x-3) (3x +2) - (4x+ 7) (x+4) = (2x + 1) (5x-1)
3. 2x^2 + (x -1) (x+1)= 5x (x+10
4. 4- ( x-1) (x+5) - (x+2) (x+5) = 3(x-1) (x+2)
😭😭😭🌚🌚🌚😞😞😞
1. x+2/x-2-1/x=2/x(x-2)
2. 5x +2(x-2)=17
3. x+3x+2/2=1-5x/6
4. x^2 . -16 =3(x-4)
5. x/x-1-x+1/2x+3=1+4x/(x-1)(2x+3)
6. 3x+1=7x-11
7. (x-1)(3x+2)=0
8. 3x-2=-14
9. (4x-2)(3x+5)=0
10. 2x+1/3-7x+5/15=x-2/5
Tìm các giá trị của x để giá trị các biểu thức sau bằng 0 :
a, \(\dfrac{x^2-x}{x^2+x+1}\)
b, \(\dfrac{x+1}{x\left(x+2\right)}\)
c, \(\dfrac{x^2-1}{x^2+3}\)
d, \(\dfrac{98x^2-2}{x-2}\)
e, \(\dfrac{3x-2}{x^2+2x+1}\)
f, \(\dfrac{x}{x^2-4}\)- \(\dfrac{3-x}{\left(x+2\right)^2}\)
a. (x+1) (x-2) e. (3x+1)(x+\(\dfrac{1}{2}\))
b. (2x-3) (x-4) f. (x\(^3\)-2x+6)(5-\(\dfrac{2}{3}\)xy)
c. (x-1)(x+3)(x-2)
d. (x-5)(x+\(\dfrac{1}{2}\))
Cho biểu thức:
A=\(\left(\dfrac{x}{x^2-4}+\dfrac{2}{2-x}+\dfrac{1}{x+2}\right):\left(x-2+\dfrac{10-x^2}{x+2}\right)\)
a. Rút gọn A
b. Tính giá trị biểu thức A tại x, biết /x/=\(\dfrac{1}{2}\)
c. Tìm giá trị của x để A<0