\(27^3+9^5=\left(3^3\right)^3+\left(3^2\right)^5=3^9+3^{10}=3^9\cdot\left(1+3\right)=4\cdot3^9⋮4\)
Ta có: 273+95=33.93+95=93.(33+92)=93.108=93.27.4\(⋮4\)
\(27^3+9^5=3^9+3^{10}=3^9\left(1+3\right)=3^9\cdot4⋮4\)
Ta có: 273+95=33.93+95=93.(33+92)=93.108=93.4⋮4