a/ \(\Delta ABC\) có : AB = AC
\(\Leftrightarrow\Delta ABC\) cân tại A
\(\Leftrightarrow\widehat{B}=\widehat{C}\) (2 góc ở đáy)
Xét \(\Delta BDM;\Delta CEM\) có :
\(\left\{{}\begin{matrix}\widehat{BDM}=\widehat{CEM}=90^0\\MB=MC\\\widehat{B}=\widehat{C}\end{matrix}\right.\)
\(\Leftrightarrow\Delta BDM=\Delta CEM\left(ch-gn\right)\)
\(\Leftrightarrow MD=ME\)