ĐKXĐ: \(x\notin\left\{1;-1\right\}\)
a) Ta có: \(C=\left(x^2-1\right)\cdot\left(\dfrac{1}{x-1}-\dfrac{1}{x+1}+1\right)\)
\(=\left(x^2-1\right)\cdot\left(\dfrac{x+1}{\left(x-1\right)\left(x+1\right)}-\dfrac{x-1}{\left(x+1\right)\left(x-1\right)}+\dfrac{x^2-1}{\left(x-1\right)\left(x+1\right)}\right)\)
\(=\left(x^2-1\right)\cdot\dfrac{x+1-x+1+x^2-1}{\left(x+1\right)\left(x-1\right)}\)
\(=x^2-1\)