\(M=\sqrt{\left(a+\frac{1}{2}\right)^2+\left(\frac{\sqrt{15}}{2}\right)^2}+\sqrt{\left(b+\frac{1}{2}\right)^2+\left(\frac{\sqrt{15}}{2}\right)^2}+\sqrt{\left(c+\frac{1}{2}\right)^2+\left(\frac{\sqrt{15}}{2}\right)^2}\)
\(M\ge\sqrt{\left(a+b+c+\frac{3}{2}\right)^2+\left(\frac{3\sqrt{15}}{2}\right)^2}=3\sqrt{6}\)
\(M_{min}=3\sqrt{6}\) khi \(a=b=c=1\)
\(M_{max}\) ko tồn tại