\(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Rightarrow\dfrac{b}{a}=\dfrac{d}{c}\)
\(\Rightarrow\dfrac{b}{a}-1=\dfrac{d}{c}-1\)
\(\Rightarrow\dfrac{b-a}{a}=\dfrac{d-c}{c}\Rightarrow-\left(\dfrac{b-a}{a}\right)=-\left(\dfrac{d-c}{c}\right)\)
\(\Rightarrow\dfrac{a-b}{a}=\dfrac{c-d}{c}\left(đpcm\right)\)
ta có: a/b=c/d
=> ad=cb =>ac-ad=ac-cb
<=> a(c-d)=c(a-b)
=>a/a-b=c/c-d